MATH SOLVE

4 months ago

Q:
# 1/2 + 5/3 - 1------------------ 3/4

Accepted Solution

A:

Hey there :)

[tex] \frac{ \frac{1}{2}+ \frac{5}{3} -1 }{ \frac{3}{4} } [/tex]

↓ Is the same as

[tex] \frac{1}{2} + \frac{5}{3} -1[/tex] ÷ [tex] \frac{3}{4} [/tex]

Since it is a division by fraction, we can multiply by what is called the reciprocal

( The attached picture might help you )

( [tex] \frac{1}{2} + \frac{5}{3} - 1[/tex] ) × [tex] \frac{4}{3} [/tex]

↓ For this part, we need the common denominator, which is 6

[tex] \frac{1(3)}{2(3)}+ \frac{5(2)}{32)} \frac{1(6)}{1(6)} [/tex] × [tex] \frac{4}{3} [/tex]

[tex] \frac{3}{6}+ \frac{10}{6} - \frac{6}{6} [/tex] × [tex] \frac{4}{3} [/tex]

[tex] \frac{7}{6} [/tex] × [tex] \frac{4}{3} [/tex]

[tex] \frac{14}{9} = 1\frac{5}{9} [/tex]

↑

Your final answer

[tex] \frac{ \frac{1}{2}+ \frac{5}{3} -1 }{ \frac{3}{4} } [/tex]

↓ Is the same as

[tex] \frac{1}{2} + \frac{5}{3} -1[/tex] ÷ [tex] \frac{3}{4} [/tex]

Since it is a division by fraction, we can multiply by what is called the reciprocal

( The attached picture might help you )

( [tex] \frac{1}{2} + \frac{5}{3} - 1[/tex] ) × [tex] \frac{4}{3} [/tex]

↓ For this part, we need the common denominator, which is 6

[tex] \frac{1(3)}{2(3)}+ \frac{5(2)}{32)} \frac{1(6)}{1(6)} [/tex] × [tex] \frac{4}{3} [/tex]

[tex] \frac{3}{6}+ \frac{10}{6} - \frac{6}{6} [/tex] × [tex] \frac{4}{3} [/tex]

[tex] \frac{7}{6} [/tex] × [tex] \frac{4}{3} [/tex]

[tex] \frac{14}{9} = 1\frac{5}{9} [/tex]

↑

Your final answer