MATH SOLVE

3 months ago

Q:
# Identify any extraneous solution. See above pic

Accepted Solution

A:

Answer:There are no extraneous solutionsReasoning:An extraneous solution is a solution that isn't valid, it might be imaginary like the square root of a negative number.first we want to isolate z:1+sqrt(z)=sqrt(z+5)^2 all ^2 all(1+sqrt(z))(1+sqrt(z))=z+5expand1+2sqrt(z)+z=z+5-1 -z -z -12sqrt(z)=4/2 /2sqrt(z)=2^2 all ^2 allz=4Since there is one solution and it is a real number, there are no extraneous solutions.