MATH SOLVE

4 months ago

Q:
# what is the scale factor in the dilation if the coordinates of A' are (-7,6) and the coordinates of C' are (-4,3)A)1/3B)1/2C)2D)3 PLZ HELPP

Accepted Solution

A:

Answer:

1/3

Explanation:

The general rule to get the new dilation coordinate is as follows:

new coordinate = k * old coordinate

where k is the scale factor

For point A:

Xcoordinate of A' = k * Xcoordinate of A

-7 = k * -21

k = -7 / -21

k = 1/3

Ycoordinate of A' = k * Ycoordinate of A

6 = k * 18

k = 6/18

k = 1/3

For point C:

Xcoordinate of C' = k * Xcoordinate of C

-4 = k * -12

k = -4/-12

k = 1/3

Ycoordinate of C' = k * Ycoordinate of C

3 = k * 9

k = 3/9

k = 1/3

From all of the above, we can conclude that the scale factor is definitely 1/3

Hope this helps :)

1/3

Explanation:

The general rule to get the new dilation coordinate is as follows:

new coordinate = k * old coordinate

where k is the scale factor

For point A:

Xcoordinate of A' = k * Xcoordinate of A

-7 = k * -21

k = -7 / -21

k = 1/3

Ycoordinate of A' = k * Ycoordinate of A

6 = k * 18

k = 6/18

k = 1/3

For point C:

Xcoordinate of C' = k * Xcoordinate of C

-4 = k * -12

k = -4/-12

k = 1/3

Ycoordinate of C' = k * Ycoordinate of C

3 = k * 9

k = 3/9

k = 1/3

From all of the above, we can conclude that the scale factor is definitely 1/3

Hope this helps :)