How many yards of the fencing materials do they need for the fence ? explain

Answer:152.7 ydStep-by-step explanation:I presume that there is a fence around the perimeter and separating the various plots.AG = BF  = CE = 18 ydGH = DE = 12 ydEO² = DE² + DO²1 5² = 12²  + DO²225 = 144 + DO²   81 = DO²DO = 9BC = DO = EF  = 9 ydAC = DH =  EG = 17 ydAO² = AB² + BO² = 8² + 6² = 64 + 36 =100AO = √100 = 10 ydCO² = BC² + BO² = 9² + 6² = 81 + 36 = 127 CO = √127 ydGO² = FG² + FO² = 8² + 12² =64 + 144 = 208 GO = √208 = 4√13 ydFencing needed= (AC + DH + EG) + (AG + BF + CE) + AO +   CO  + EO + GO=        (3 × 17)        +         3 × 18)       + 10   + √127 + 15  + 4√13=           51            +            54          + 25   +  11.27 +          14.42  =       152.7 yd